boxhist.csv draw a histogram, and a boxplot. Based on the graphics, answer the following questions or check the correct statements, respectively. (Comment: The tolerance for numeric answers is \(\pm0.2\), the true/false statements are either about correct or clearly wrong.)
Answerlist
The distribution is unimodal.
The distribution is not unimodal.
The distribution is symmetric.
The distribution is right-skewed.
The distribution is left-skewed.
The boxplot shows outliers.
The boxplot shows no outliers.
A quarter of the observations is smaller than which value?
A quarter of the observations is greater than which value?
Half of the observations are greater than which value?
Lösung
Answerlist
True.
False.
True.
False.
False.
True.
False.
3.44.
4.58.
Categories:
vis
eda
en
cloze
Source Code
---extype: clozeexsolution: r paste(solutions, collapse = "|")exclozetype: r paste(type, collapse = "|")exname: boxhistextol: r tolcategories:- vis- eda- en- clozedate: '2023-02-26'slug: boxhisttitle: boxhist---```{r data generation, echo = FALSE, results = "hide"}## DATAlibrary(exams)n <-sample(30:50, 1)m <-sample(1:4, 1)s <-runif(1, 0.5, 2)delta <-ifelse(runif(1) <0.2, sample(8:12), 0)p2 <-runif(1, 0.45, 0.55)skewed <- left <-FALSEif(!delta) { skewed <-runif(1) <0.6 left <-runif(1) <0.3}dgpBoxhist <-function(n =40, mean =0, sd =1, delta =0,p2 =0.5, skewed =FALSE, left =FALSE){ SK <-function(x) abs(diff(diff(fivenum(x)[2:4]))/diff(fivenum(x)[c(2, 4)])) sim <-function(x){ x <-rnorm(n)if(skewed) exp(x) else x } x <-sim()if(skewed) while(SK(x) <0.7) x <-sim() elsewhile(SK(x) >0.15) x <-sim()if(left) x <--x x <- mean + sd *scale(x) k <-sample(1:n, round(p2 * n)) x[k] <- x[k] + deltaas.vector(sample(x))}x <-round(dgpBoxhist(n = n, mean = m, sd = s, delta = delta, p2 = p2, skewed = skewed, left = left), digits =2)b <-boxplot(x, plot =FALSE)spread <- tol <-signif(diff(range(c(b$stats, b$out)))/25, 1)write.csv(data.frame(x), file ="boxhist.csv", quote =FALSE, row.names =FALSE)## QUESTION/SOLUTIONquestions <- solutions <- explanations <-rep(list(""), 6)type <-rep(list("schoice"), 6)questions[[1]] <-paste("The distribution is ", c("", "_not_ "), "unimodal.", sep ="")solutions[[1]] <-c(delta <1, delta >1)questions[[2]] <-paste("The distribution is", c("symmetric.", "right-skewed.", "left-skewed."))solutions[[2]] <-c(!skewed, skewed &!left, skewed & left)questions[[3]] <-paste("The boxplot shows ", c("", "_no_ "), "outliers.", sep ="")solutions[[3]] <-c(length(b$out) >0, length(b$out) <1)questions[[4]] <-"A quarter of the observations is smaller than which value?"solutions[[4]] <- explanations[[4]] <-signif(b$stats[[2]], 3)type[[4]] <-"num"questions[[5]] <-"A quarter of the observations is greater than which value?"solutions[[5]] <- explanations[[5]] <-signif(b$stats[[4]], 3)type[[5]] <-"num"questions[[6]] <-paste("Half of the observations are",sample(c("smaller", "greater"), 1), "than which value?")solutions[[6]] <- explanations[[6]] <-signif(b$stats[[3]], 3)type[[6]] <-"num"explanations[1:3] <-lapply(solutions[1:3], function(x) ifelse(x, "True", "False"))solutions[1:3] <-lapply(solutions[1:3], mchoice2string)if(any(explanations[4:6] <0)) explanations[4:6] <-lapply(solutions[4:6], function(x) paste("$", x, "$", sep =""))```# Aufgabe[boxhist.csv](boxhist.csv) draw a histogram, and a boxplot.Based on the graphics, answer the following questions or check the correctstatements, respectively. _(Comment: The tolerance for numeric answers is$\pm`r tol`$, the true/false statements are either about correct or clearly wrong.)_```{r questionlist, echo = FALSE, results = "asis"}answerlist(unlist(questions), markup ="markdown")```</br></br></br></br></br></br></br></br></br></br># Lösung```{r boxplot_hist, echo = FALSE, results = "hide", fig.height = 4.5, fig.width = 9, fig.path = "", fig.cap = ""}par(mfrow =c(1, 2))boxplot(x, axes =FALSE)axis(2, at =signif(b$stats, 3), las =1)box()hist(x, freq =FALSE, main ="")rug(x)``````{r solutionlist, echo = FALSE, results = "asis"}answerlist(paste(unlist(explanations), ".", sep =""), markup ="markdown")```---Categories: - vis- eda- en- cloze
